Leetcode [Easy] 128 - Implement strStr()
Leetcode 28
Implement strStr()
문제
Implement strStr().
Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Clarification:
What should we return when needle is an empty string? This is a great question to ask during an interview.
For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().
Example 1:
Input: haystack = "hello", needle = "ll"
Output: 2
Example 2:
Input: haystack = "aaaaa", needle = "bba"
Output: -1
Example 3:
Input: haystack = "", needle = ""
Output: 0
Constraints:
0 <= haystack.length, needle.length <= 5 * 104
haystack and needle consist of only lower-case English characters.
나의 코드
/**
* @param {string} haystack
* @param {string} needle
* @return {number}
*/
const strStr = function (haystack, needle) {
if (haystack === needle || needle.length === 0) return 0;
const lengthOfSearchBundle = needle.length;
for (let i = 0; i <= haystack.length - lengthOfSearchBundle; i++) {
const bundle = haystack.slice(i, i + lengthOfSearchBundle);
if (bundle === needle) return i;
}
return -1;
};
참고 코드
var strStr = function (haystack, needle) {
if (needle.length == 0) return 0;
for (let i = 0; i < haystack.length; i++) {
let k = i,
j = 0;
while (haystack[k] == needle[j] && j < needle.length) {
k++, j++;
}
if (j == needle.length) return i;
}
return -1; // couldn't find needle in haystack
// Time Complexity: O(m*n)
// Space Complexity: O(1)
};
배운점
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